Posted: Thu Aug 22, 2024 8:55 am Post subject: Why is my address 32 bits?
I've checked that the platform of cheat engine and attached process (Solitaire.exe) are all 64-bit.
When I open the memory view form, I only see 32 bit address on the left.
I attach a snapshot for better understanding.
By the way, I use the "allocate memory" in the "tools".
CE formats addresses using at least 8 hex characters, padding the start with zeros if necessary. Extra leading zeros are implicit
03E0FFFE == 0000000003E0FFFE
Same thing with the addresses in the hex view. They aren't 6-byte addresses; they're 8-byte with implicit leading zeros
7FF63902F000 == 00007FF63902F000 _________________
I don't know where I'm going, but I'll figure it out when I get there.
CE formats addresses using at least 8 hex characters, padding the start with zeros if necessary. Extra leading zeros are implicit
03E0FFFE == 0000000003E0FFFE
Same thing with the addresses in the hex view. They aren't 6-byte addresses; they're 8-byte with implicit leading zeros
7FF63902F000 == 00007FF63902F000
In the case, how could you explain the below panel, a hex "0" and a hex "7FF63902F000" makes a long int? It indicates that a address can be 64-bit.
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