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Help with what I assume is a VERY simple question to you all

 
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Goat Engine
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PostPosted: Mon Jan 06, 2020 8:29 pm    Post subject: Help with what I assume is a VERY simple question to you all Reply with quote
I have a line I'm trying to change. The original code is:
Code:
movzx eax,byte ptr [rax+rcx]

And what I want to do is make the number being moved into eax be a 1 byte zero. My idea to accomplish this, based on past coding I had success with in CE scripts, was this...
Code:
mov eax, byte ptr 0

It fails.
Right off the bat I have a feeling you guys see a problem I don't.

Anyway, having been self learning cheat engine and everything it does, I haven't yet found anything that can clarify for me the mindset I should be using with the above line and why the auto assembler script tells me it WON'T work, no matter how I rearrange it?

I've used a similar line in the past to move a 0 without any problems. Only difference is today it's "eax" as the variable I'm trying to move 0 to instead of others. What's happening and is this specifically because it's eax? How does a person write this line when they want it to work exactly as I'm intending here, and is there any documentation that's cheat engine user friendly that sums up why I'm having an issue without being as complicated as if I just google for assembly help?
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ParkourPenguin
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PostPosted: Mon Jan 06, 2020 11:06 pm    Post subject: Reply with quote
"byte ptr" is used to refer to addresses. Remove it.
Code:
mov eax,0

A functionally equivalent but better way is to use xor:
Code:
xor eax,eax
// eax is now 0


If you only want to change one byte but leave everything else in eax alone, use the al register instead:
Code:
mov al,0
// or:
xor al,al

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Goat Engine
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Posts: 44
PostPosted: Tue Jan 07, 2020 2:54 am    Post subject: Reply with quote
Ah, makes perfect sense. These tips will also help me with some things I plan on doing in the future too, so double thank you!! (I had a follow up question in my other thread you helped me in though, if you get time)
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