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Razi
Expert Cheater
 Reputation: 1
Joined: 17 Jan 2018
Posts: 205
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 Posted: Wed Apr 03, 2019 9:04 am Post subject: How to change list in a combobox1 with combobox2? |
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I have three questions:
1) How to change list in a combobox1 with combobox2?How to change combobox1 list? For example,in combobox1, the list consists 90 Items: Item1, Item2, Item3 ... Item90.
if in combobox2 the ItemIndex is 0, then show only: Item1, Item4, Item5 in combobox1.
if in combobox2 the ItemIndex is 1, then show only: item5, item7, item10, item50 in combobox1
2) Is it possible to improve the following code?
| Code: | function materiatype()
if UDF1["CEComboBox"..2].ItemIndex == 0 then
UDF1.CEComboBox1.Items.clear()
for k,v in pairs(materialisttbl) do
UDF1.CEComboBox1.Items.Add(v)
end
elseif UDF1["CEComboBox"..2].ItemIndex == 1 then
UDF1.CEComboBox1.Items.clear()
for i = 0x31, 0x49 do
UDF1.CEComboBox1.Items.Add(materialisttbl[i])
end
UDF1.CEComboBox1.Items.Add(materialisttbl[0xFF])
elseif UDF1["CEComboBox"..2].ItemIndex == 2 then
UDF1.CEComboBox1.Items.clear()
for i = 0x17, 0x23 do
UDF1.CEComboBox1.Items.Add(materialisttbl[i])
end
UDF1.CEComboBox1.Items.Add(materialisttbl[0xFF])
elseif UDF1["CEComboBox"..2].ItemIndex == 3 then
UDF1.CEComboBox1.Items.clear()
for i = 0x0E, 0x0F do
UDF1.CEComboBox1.Items.Add(materialisttbl[i])
end
for i = 0x13, 0x15 do
UDF1.CEComboBox1.Items.Add(materialisttbl[i])
end
for i = 0x24, 0x2C do
UDF1.CEComboBox1.Items.Add(materialisttbl[i])
end
UDF1.CEComboBox1.Items.Add(materialisttbl[0x30])
UDF1.CEComboBox1.Items.Add(materialisttbl[0xFF])
elseif UDF1["CEComboBox"..2].ItemIndex == 4 then
UDF1.CEComboBox1.Items.clear()
for i = 0x00, 0x0D do
UDF1.CEComboBox1.Items.Add(materialisttbl[i])
end
for i = 0x10, 0x12 do
UDF1.CEComboBox1.Items.Add(materialisttbl[i])
end
UDF1.CEComboBox1.Items.Add(materialisttbl[0xFF])
elseif UDF1["CEComboBox"..2].ItemIndex == 5 then
UDF1.CEComboBox1.Items.clear()
for i = 0x4A, 0x5A do
UDF1.CEComboBox1.Items.Add(materialisttbl[i])
end
UDF1.CEComboBox1.Items.Add(materialisttbl[0xFF])
end
end |
3) How to get all the numbers in the table?
Example:
| Code: | t = { {5, 6, 7}, {8, 9, 10} }
print(t[2][2])
-- result 9 |
How to get in result 8, 9, 10 ?
The following code does not work:
| Code: | t = { {5, 6, 7}, {8, 9, 10} }
print(t[2]) |
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Corroder
Grandmaster Cheater Supreme
 Reputation: 75
Joined: 10 Apr 2015
Posts: 1668
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| Posted: Wed Apr 03, 2019 11:04 am Post subject: |
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| Quote: | 1. if in combobox2 the ItemIndex is 0, then show only: Item1, Item4, Item5 in combobox1.
if in combobox2 the ItemIndex is 1, then show only: item5, item7, item10, item50 in combobox1
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sample: I use tables but it close to combobox.
| Code: | data = {"Item1","Item2","Item3","Item4","Item5","Item6","Item6","Item8","Item9","Item10",
"Item20","Item50","Item90"}
combo1 = {}
combo2 = {0,1} -- since don't know if combo2 items are same with combo1 items or not
index = combo2[0] -- try chane to 1
if index then
table.insert(combo1,{data[1],data[4],data[5]})
else
table.insert(combo1,{data[5],data[10],data[12]})
end
for k, v in ipairs(combo1) do
--print(k)
for i=1, #v do print(v[i]) end
print() -- This will just print a new line
end
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Remember lua table index start with 0
| Quote: | | 3. How to get all the numbers in the table?. How to get in result 8, 9, 10 ? |
| Code: | t = {{5, 6, 7},{8, 9, 10}}
-- show how much index on table t
print('Index data on table t = '..#t)
print(" ") -- This will just print a new line
-- show all
for k, v in ipairs(t) do
--print(k)
for i=1, #v do print(v[i]) end
print() -- This will just print a new line
end
--for show t.index[2]
print(" ") -- This will just print a new line
for i=1,3 do
print(t[2][i])
end |
_________________
Stealing Code From Stolen Code...
And Admit It.. Hmmm....Typically LOL |
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Razi
Expert Cheater
Reputation: 1
Joined: 17 Jan 2018
Posts: 205
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| Posted: Wed Apr 03, 2019 1:38 pm Post subject: |
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Thanks, it helped.
Can we add different pictures to the combobox Items?
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