Cheat Engine

gogodr · Posted: Tue Oct 06, 2009 4:30 pm Post subject: MichealRein

In an acute-angled triangle ABC, draw height BH (H on AC). Then place points Q and M on BH and HC, respectively, so AQM is a rectangle triangle, straight in Q. if AM = MC and BC^2 - AB^2 = 144, find QM.

Answer

AM = MC

yes but there is no multiplication or nothing, they are distances in the triangle :/

I'm going to call AM == a and AH == m

BC^2 = AB^2 + AC^2 - 2(AC)(AH) ** propriety
BC^2 - AB^2 = (2a)^2 - 2(2a)(m)
BC^2 - AB^2 = 4a(a-m)

144 = 4a(a-m)

a(a-m)= 36

QM^2 = (AM)(HM)

QM^2 = a(a-m)
QM^2 = 36

QM = 6

Jake! · Posted: Tue Oct 06, 2009 4:41 pm Post subject:

Oh, so AM and MC are line segments?

Holy shit MichaelRein have you even taken Geometry? It's not even a freshman level course in most places.

Cryoma · Posted: Tue Oct 06, 2009 4:43 pm Post subject:

gogodr · Posted: Tue Oct 06, 2009 4:43 pm Post subject:

yes, and xP the problem is university lvl though its the easiest one from the book.

Jake! · Posted: Tue Oct 06, 2009 4:44 pm Post subject:

[SPW]Killamoocow · Posted: Tue Oct 06, 2009 4:55 pm Post subject:

I know an 8th grader that has Algebra 2. No lie. We normally do algebra 1 in 8th grade (or if you don't pass some test in 7th grade, you get Algebra 1 in 8th)

Mi/c/healRein · Posted: Tue Oct 06, 2009 4:59 pm Post subject: