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2 data variable

 
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kucingkembar
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PostPosted: Sun Jul 17, 2022 10:49 am    Post subject: 2 data variable Reply with quote

sorry for my bad english,
i have mini database like this
Code:
id   name    weapon
01   Crono    Katanas
02   Marle    Bows   
03   Lucca    Guns   
04   Robo    Mechanical Arms   
05   Frog    Swords   
06   Ayla    Fists   
07   Magus    Scythes   

and this is sample of my code
Code:
HeroID = {}
HeroID[1] = "Crono"
--do same until Magus

HeroWeapon = {}
HeroWeapon[1] = "Katanas"
--do same until Scythes

is there any syntax that make that both variable into 1 line?
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AylinCE
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PostPosted: Sun Jul 17, 2022 12:25 pm    Post subject: Reply with quote

Simple:
Code:
HeroID = {}
HeroID[1] = "Crono"

HeroWeapon = {}
HeroWeapon[1] = "Katanas"

res = HeroID[1].." = "..HeroWeapon[1]
print(res)


Single table:
Code:
HeroAll = {Crono="Katanas",
Marle="Bows",
Lucca="Guns",
Robo="Mechanical Arms",
Frog="Swords",
Ayla="Fists",
Magus="Scythes"}

for i,k in pairs(HeroAll) do
print(i.." - "..k)
end

id = "Lucca"
print("\nLucca: "..HeroAll[id])
print("Marle: "..HeroAll.Marle)


Comprehensive:
Code:
Hero = [[Crono
Marle
Lucca
Robo
Frog
Ayla
Magus]]

Weapon = [[Katanas
Bows
Guns
Mechanical Arms
Swords
Fists
Scythes]]

HeroID = {}
HeroWeapon = {}
HeroIDWeapon = {}

sl1 = createStringList()
sl1.Text = Hero

sl2 = createStringList()
sl2.Text = Weapon

for i=0, sl1.Count -1 do
HeroID[i+1] = sl1[i]
HeroWeapon[i+1] = sl2[i]
end

sl1.Destroy()
sl2.Destroy()

for i=1, #HeroID do
 HeroIDWeapon[i] = HeroID[i]
 HeroIDWeapon[HeroID[i]] = HeroWeapon[i]
end

for i,k in pairs(HeroIDWeapon) do
print(i,k)
end


Take what you need from the examples.

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ParkourPenguin
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PostPosted: Sun Jul 17, 2022 1:41 pm    Post subject: Reply with quote

Do you mean combining the HeroID and HeroWeapon tables? Make it a table of tables:
Code:
Heros = {
  {
    id = '01',
    name = 'Crono',
    weapon = 'Katanas',
  },
  {
    id = '02',
    name = 'Marle',
    weapon = 'Bows',
  },
  -- ...
}

for i,v in ipairs(Heros) do
  print(('%d: id = %s, name = %s, weapon = %s'):format(i, v.id, v.name, v.weapon))
end

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kucingkembar
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PostPosted: Sun Jul 17, 2022 11:07 pm    Post subject: Reply with quote

thank you AylinCE, But ParkourPenguin method is what I looking for,

thank you ParkourPenguin, your answer is works

EDIT:
how to: i like to print only "weapon" with id of "05"?
Nevermind, it like this "print(Heros[1].name)"
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AylinCE
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PostPosted: Tue Jul 19, 2022 2:28 am    Post subject: Reply with quote

Code:
Heros = {
  {
    id = '01',
    name = 'Crono',
    weapon = 'Katanas',
  },
  {
    id = '02',
    name = 'Marle',
    weapon = 'Bows',
  },
  -- ...
}

function searchTbl(a,fnd)
res = "not found!"
for i,v in ipairs(Heros) do
 if v.id==a then
  if fnd==1 then
   res = v.name
  elseif fnd==2 then
   res = v.weapon
  else
  res = ('%d: id = %s, name = %s, weapon = %s'):format(i, v.id, v.name, v.weapon)
  end
 end
return res
end

aa1 = searchTbl("05",1)
aa2 = searchTbl("05",2)
aa3 = searchTbl("04",3)
print (aa1)
print (aa2)
print (aa3)

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Corroder
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PostPosted: Tue Jul 19, 2022 8:17 pm    Post subject: Reply with quote

AylinCE wrote:
Code:
Heros = {
  {
    id = '01',
    name = 'Crono',
    weapon = 'Katanas',
  },
  {
    id = '02',
    name = 'Marle',
    weapon = 'Bows',
  },
  -- ...
}

function searchTbl(a,fnd)
res = "not found!"
for i,v in ipairs(Heros) do
 if v.id==a then
  if fnd==1 then
   res = v.name
  elseif fnd==2 then
   res = v.weapon
  else
  res = ('%d: id = %s, name = %s, weapon = %s'):format(i, v.id, v.name, v.weapon)
  end
 end
return res
end

aa1 = searchTbl("05",1)
aa2 = searchTbl("05",2)
aa3 = searchTbl("04",3)
print (aa1)
print (aa2)
print (aa3)


1. Need one more "end" statement to close the function
2. Avoid the function to show "not found", if find data on the table has success and finding process has reach the and of the table
3. Note, Lua table index start from 1

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AylinCE
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PostPosted: Wed Jul 20, 2022 12:13 am    Post subject: Reply with quote

I wrote the code on the phone in answer mode, I didn't get a chance to try it.
An "end" factor and cascading inserts were made.
In my case the latest version is working.


Code:

 Heros = {
  {
    id = '01',
    name = 'Crono',
    weapon = 'Katanas',
  },
  {
    id = '02',
    name = 'Marle',
    weapon = 'Bows',
  },
  -- ...
}

function searchTbl(a,fnd)
res = ""
for i,v in ipairs(Heros) do
 if a==v.id then
  if fnd==1 then
   res = v.name
  elseif fnd==2 then
   res = v.weapon
  elseif fnd==3 then
   res = v.name.." "..v.weapon
  else
  res = ('%s %s %s'):format(v.id, v.name, v.weapon)
  end
 end
 end
return res
end

aa1 = searchTbl("01",1)
aa2 = searchTbl("01",2)
aa3 = searchTbl("02",3)
aa0 = searchTbl("01",0)
print (aa1)
print (aa2)
print (aa3)
print (aa0)


result:

Crono
Katanas
Marle Bows
01 Crono Katanas

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