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Anarchy
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 Posted: Wed Sep 08, 2010 10:42 pm Post subject: Stuck again, halp. |
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This one is just sort of confusing me.
I feel like a retard :c.
The measure of a supplement of an angle is 12 degrees greater than three times the measure of a complement. Find the measure of the angle.
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majjikelkitty
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| Posted: Wed Sep 08, 2010 10:43 pm Post subject: |
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| That angle must like getting complemented...
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Anarchy
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| Posted: Wed Sep 08, 2010 10:43 pm Post subject: |
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lol ben.
THIS IS SERIOUS BUSINESS ;~;
I MUST FINISH QUICKLY SO I CAN BEGIN MY OTHER WORK.
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xXL3G10N~4~LYFEXx
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| Posted: Wed Sep 08, 2010 10:44 pm Post subject: |
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Complimentary angles are 90 degrees.
Supplementary angles are 180.
Im too tired to figure the rest.
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Anarchy
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| Posted: Wed Sep 08, 2010 10:44 pm Post subject: |
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| Legion~ wrote: | Complimentary angles are 90 degrees.
Supplementary angles are 180.
Im too tired to figure the rest. |
I knew that.
Thanks though.
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Ricardo
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| Posted: Wed Sep 08, 2010 10:45 pm Post subject: Re: Stuck again, halp. |
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| Anarchy wrote: | This one is just sort of confusing me.
I feel like a retard :c.
The measure of a supplement of an angle is 12 degrees greater than three times the measure of a complement. Find the measure of the angle. |
supplementary should be 180 degrees... complementary is 90.
so
x = 12+ (3 (90-x)
should be right. double check because I'm not too sure about it.
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Crinchy
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| Posted: Wed Sep 08, 2010 10:48 pm Post subject: |
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| Die, Retardo.
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Anarchy
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| Posted: Wed Sep 08, 2010 10:48 pm Post subject: Re: Stuck again, halp. |
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| Ricardo wrote: | | Anarchy wrote: | This one is just sort of confusing me.
I feel like a retard :c.
The measure of a supplement of an angle is 12 degrees greater than three times the measure of a complement. Find the measure of the angle. |
supplementary should be 180 degrees... complementary is 90.
so
x = 12+ (3 (90-x)
should be right. double check because I'm not too sure about it. |
Man, I am glad you are here right now, Ricardo. lol.
Sorry if this is a little pestering, but could you help me with another?
The degree measures of the angles of a pentagon are consecutive even integers. Find the measure of the largest angle. (Hint: The sum of the measures of the angles of a pentagon is 540 degrees.)
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Ricardo
I post too much
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| Posted: Wed Sep 08, 2010 10:52 pm Post subject: Re: Stuck again, halp. |
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| Anarchy wrote: | | Ricardo wrote: | | Anarchy wrote: | This one is just sort of confusing me.
I feel like a retard :c.
The measure of a supplement of an angle is 12 degrees greater than three times the measure of a complement. Find the measure of the angle. |
supplementary should be 180 degrees... complementary is 90.
so
x = 12+ (3 (90-x)
should be right. double check because I'm not too sure about it. |
Man, I am glad you are here right now, Ricardo. lol.
Sorry if this is a little pestering, but could you help me with another?
The degree measures of the angles of a pentagon are consecutive even integers. Find the measure of the largest angle. (Hint: The sum of the measures of the angles of a pentagon is 540 degrees.) |
consecutive even integers.
540/5 bro.
108
that's the average of those 5 degree measurements.
112
check:
112 + 108 + 110 + 106 + 104
You'll be doing this type of problem on the SAT, no doubt.
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Anarchy
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| Posted: Wed Sep 08, 2010 10:54 pm Post subject: Re: Stuck again, halp. |
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| Ricardo wrote: | | Anarchy wrote: | | Ricardo wrote: | | Anarchy wrote: | This one is just sort of confusing me.
I feel like a retard :c.
The measure of a supplement of an angle is 12 degrees greater than three times the measure of a complement. Find the measure of the angle. |
supplementary should be 180 degrees... complementary is 90.
so
x = 12+ (3 (90-x)
should be right. double check because I'm not too sure about it. |
Man, I am glad you are here right now, Ricardo. lol.
Sorry if this is a little pestering, but could you help me with another?
The degree measures of the angles of a pentagon are consecutive even integers. Find the measure of the largest angle. (Hint: The sum of the measures of the angles of a pentagon is 540 degrees.) |
consecutive even integers.
540/5 bro.
108
that's the average of those 5 degree measurements.
112
check:
112 + 108 + 110 + 106 + 104
You'll be doing this type of problem on the SAT, no doubt. |
Yeah, I really don't know how that just happened, but thanks.
I guess I'm a little tired or something 3: .
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Ricardo
I post too much
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| Posted: Wed Sep 08, 2010 10:55 pm Post subject: |
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Practice more.
Don't expect to be able to do this during the actual algebra course. Somehow by the time it ends, you'll be able to do these really easily.
I passed all math classes in my school with a 65 or somewhere around that.
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Anarchy
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| Posted: Wed Sep 08, 2010 11:18 pm Post subject: |
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It seems like I get every other two or three questions, then I get stumped.
If you're still on:
Elisa walked a certain distance at 5 mph, then jogged twice that distance at 8 mph. her total time walking/jogging was 2 h and 15 min. How many miles long was the walkathon?
(Hint: time = distance/rate)
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Simon :v
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| Posted: Wed Sep 08, 2010 11:25 pm Post subject: |
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x = [ -b +/- sqrt(b^2 - 4ac) ] / 2a
memorize this, you'll need it.
Last edited by Simon :v on Wed Sep 08, 2010 11:49 pm; edited 1 time in total |
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:^(
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| Posted: Wed Sep 08, 2010 11:44 pm Post subject: |
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| Takanashi Yomi wrote: | x = [ -b +/- sqrt(b^2 - 4ac) ] + 2a
memorize this, you'll need it. |
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Saucy.
How do I cheat?
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| Posted: Wed Sep 08, 2010 11:53 pm Post subject: |
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| Anarchy wrote: | It seems like I get every other two or three questions, then I get stumped.
If you're still on:
Elisa walked a certain distance at 5 mph, then jogged twice that distance at 8 mph. her total time walking/jogging was 2 h and 15 min. How many miles long was the walkathon?
(Hint: time = distance/rate) |
15 Miles, yo.
Walked for five miles in one hour, leaving an hour and 15 minutes for jogging.
8*1.25=10 miles
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