Cheat Engine

[Eh520]

in a game, i said "a" and "b" at i recorded down the two diff packets of those two.

"a"
41 00 B5 33 44 3D 12 56 44 9A BB 33 C9 3F 12 56 44 9A BB 33 46 3F 00 56 44 9A BB 33 E4 3A 12 56 2C 74 4A 31 BB C0 12 56 04 6B 4A 31 54 3F 12 56 34 74 4A 31 44 3F 12 56 88 9A 63 3B A3 CA 18 37 44 9B 44

"b"
41 00 B5 33 44 3D 12 56 44 9A BB 33 F4 3F 12 56 15 9F 28 4F 46 3F 22 57 29 9F 28 4F 4C F8 89 41 4C 5D 20 24 44 3F 12 56 10 A2 16 24 0C CD 00 56 24 FD A4 2B E0 7C CE 41 14 D3 DA 33 0C CD 00 34 44 D3 44


i read some tutorials, but i dont know how to know how to read this hex thing and like i can send the packets as many time as i want to say "a" but what if i wanna change "a" to like "abab", what would i need to change in those packets to achieve that? i just cant understand how that kind of packets work.
please help
thanks

[Labyrnth]

When your trying to find a difference in packets you want to do some thing like.

Send a
Send A

This will have less of a change in packets possibly and you can maybe work out a simple encryption routine.

But it looks like to me the packets are encrypted.
Look at your hex you can see where they start to change after
41 00 B5 33 44 3D 12 56 44 9A BB 33

[Eh520]

after i find the difference in two packets, what can i do with it? like there are more than 3 pairs of hex number thats diff when comparing both packets.. i need to try and error? or is there any other way to actually know what number stands for what?

[Labyrnth]

Well if it is simple encryption and does the same calculation each time you can decipher packets very easily.

Say like it adds 20 hexa to the characters existing hexa, and does this the same way every time.

So if it was
A = 41 + 20 = 61
So you see 61 in the packet for A
But when you sniff a new packet and it is not 61 in the packet for A then it changes and you have more work to do to find this encryption routine.